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I have a child table that is something like this:

[Cust Date Table]

| Customer ID | Some Date  | Balance |
|           1 | 2012-04-30 |   20.00 |
|           1 | 2012-03-31 |   50.00 |
|           2 | 2012-04-30 |    0.00 |
|           2 | 2012-03-31 |   10.00 | 
|           3 | 2012-03-31 |   60.00 |
|           3 | 2012-02-29 |   10.00 |

I would like to be able to get a result set like this - one record for each client with the latest date:

| Customer ID | Some Date  | Balance |
|           1 | 2012-04-30 |   20.00 | 
|           2 | 2012-04-30 |    0.00 |
|           3 | 2012-03-31 |   60.00 |

I know that I can do this for each individual "Customer ID" with the following SQL (SQL Server syntax):

select top 1  [Some Date], [Customer ID], [Balance]
from [Cust Date Table]
where [Customer ID] = 2
order by [Some Date] desc

| Customer ID | Some Date  | Balance |
|           2 | 2012-04-30 |    0.00 |

But I'm not sure how to get all three of the records I want. I'm not sure if this is a situation that calls for a sub-query or something else.

Please note that the max date can be different for any given [Customer ID], (in this example, customer 3's maximum date is 2012-03-31 whereas the other records have a max date of 2012-04-30). I have tried

select [Customer ID], MAX([Some Date]) AS [Latest Date], Balance 
from [Cust Date Table] 
group by [Customer ID], Balance; 

The problem is this doesn't return just the one row for each customer - it returns multiple rows.

share|improve this question
up vote 13 down vote accepted

You simply want:

select [Customer ID], MAX([Some Date]) AS [Latest Date]
from [Cust Date Table]
group by [Customer ID];

Ok - you've revised it. You now want to order the rows and pick the top one:

WITH numbered AS
( SELECT [Customer ID], [Some Date], [Balance], 
     ROW_NUMBER() OVER (PARTITION BY [Customer ID] ORDER BY [Some Date] DESC) AS rownum
  FROM [Cust Date Table]
SELECT [Customer ID], [Some Date], [Balance]
FROM numbered
WHERE rownum = 1;
share|improve this answer
Oh - you've changed the question? – Rob Farley May 1 '12 at 2:59
Changed my answer now. – Rob Farley May 1 '12 at 3:03
Ok, that works. Thanks. – Joe DBA May 1 '12 at 15:01

I think you're after something like this

select c.[customer ID], [some date], balance
from [cust date table] c
inner join 
    ( select [customer ID], MAX([some date]) as maxdate
    from [cust date table]
    group by [customer ID]) c2
on c2.[customer ID] = c.[customer ID]
and c2.maxdate = c.[some date]

There are a number of variations on this, i.e. CTE, table variable, #table, that you can play around with to see what gives you the best performance in your situation.

share|improve this answer
This answer is also correct. Unfortunately I don't have enough rep to upvote it and I have to choose one answer. – Joe DBA May 1 '12 at 15:02

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