How to select distinct for one column and any in another column?

Question

I need to query an SQL database to find all distinct values of one column and I need an arbitrary value from another column. For example, consider the following table with two columns, key and value:

key     value
===     =====
one     test
one     another
one     value
two     goes
two     here
two     also
three   example

I wish to get back one sample row, chosen arbitrarily, from each distinct key, perhaps getting these three rows:

key     value
===     =====
one     test
two     goes
three   example

How can I formulate such a query in SQL?

Answer 1

The easiest query to write is for MySQL (with not strict ANSI settings). It uses the non-standard construction:

SELECT key, value
FROM tableX
GROUP BY key ;

For other DBMSs, that have window functions (like Postgres, SQL-Server, Oracle, DB2), you can use them like this. The advantage is that you can select other columns in the result as well (besides the key and value) :

SELECT key, value
FROM tableX
    ( SELECT key, value,
             ROW_NUMBER() OVER (PARTITION BY key 
                                ORDER BY whatever)     --- ORDER BY NULL
               AS rn                                   --- for example
      FROM tableX
    ) tmp 
WHERE rn = 1 ;

For older versions of the above and for any other DBMS, a general way that works almost everywhere. One disadvantage is that you cannot select other columns with this approach. Another is that aggregate functions like MIN() and MAX() do not work with some datatypes in some DBMSs (like bit, text, blobs):

SELECT key, MIN(value) AS value
FROM tableX
GROUP BY key ;

Answer 2

For MS-SQl Server:

;with FinalDataset as
(
    select *,
        row_number() over(partition by key order by value) as rownum
    from YourOriginalTable
)
select
   key,
   value
from FinalDataset 
where rownum = 1

Likewise, you could have rownum = 2 for your second result set