If SQL Server Anywhere is started via "dbsrv12.exe -z -x tcpip " it opens a Serverport.
Default is 2638.
If more then one database is opened, the other ones are getting "some" serverports.
How could I say: open the server on "this" port
In help of SQL anywhere I find: TCP/IP: Broadcast, BroadcastListener, DoBroadcast, Host, LDAP, LocalOnly, MyIP, ReceiveBufferSize, SendBufferSize, ServerPort, TDS, Timeout
dbsrv12.exe -z -x tcpip ServerPort 54382 gives 2 errors, that ServerPort and 54382 are not a file.
You can specify a single port number, or a combination of individual port numbers and ranges of port numbers. When you specify a list and/or range of port numbers, the database server attempts to bind to all specified port numbers. For example: (port=1234)
Default TCP/IP 2638
Therfore i tried
dbsrv12.exe -z -x tcpip (port=54382) and
dbsrv12.exe -z -x tcpip 54382, both giving the same error as above.
In which way do I misunderstand the help?