5
votes
3answers
2k views

How to SELECT multiple COUNT(*) columns with each GROUP BY having a different WHERE clause?

I have the following schema: CREATE TABLE Person ( PersonId int PRIMARY KEY ) CREATE TABLE Action ( ActionId int PRIMARY KEY, PersonId int NOT NULL FOREIGN KEY REFERENCES Person(PersonId), ...
0
votes
0answers
120 views

Select Foo object without any specific Bar events

Consider two tables: Foo: id INT, name VARCHAR Bar: id INT, foo_id INT REFERENCES Foo(id), event_type VARCHAR DEFAULT NULL, event_duration INT DEFAULT NULL Each Foo item can have ...
1
vote
2answers
89 views

Duplicates while doing multiple joins

I have 4 MySQL tables 1. companies - {id*, company} 2. employees - {id*, fname, lname, id_company*} 3. technologies - {id*, technology} 4. company_technologies - {id_technology*, id_company*} Field ...
4
votes
2answers
2k views

SQL join query to show rows with non-existent rows in one table

I am trying to get some reporting done for employee time records. We have two tables specifically for this question. Employees are listed in the Members table and each day they enter time entries of ...
1
vote
0answers
80 views

How to index for a group by with columns from different tables?

Is it possible to create an index from columns of 2 different tables? If not, how do we optimize a query that does a group by on columns of 2 different tables? For example: the following ...
-1
votes
2answers
2k views

How to use GROUP BY after the Having clause Mysql

Here is the query which gets the accounts for a specific user the products are related to accounts in one-to-many relation so for each product there are four permissions All the accounts which is not ...
1
vote
1answer
2k views

Error “column does not exist” in a SELECT with JOIN and GROUP BY query

I'm using PostgreSQL 9.1 with a Ruby on Rails application. I'm trying to list the last version of each "charge" (in my history table : hist_version_charges) belonging to the same project id ...
0
votes
1answer
515 views

Group By on column from joined table

its about the following query. EXPLAIN SELECT phrase, infinitiv FROM `dict_verbs_all` `t` INNER JOIN `dict_verbs_all_language` `verbsGerman_c` ON (`t`.`id`=`verbsGerman_c`.`verb_id`) INNER JOIN ...