New answers tagged sqlite
0
Many of the hits on Google seem to suggest this problem is cause by a missing "def" file. Your question does not really explain what you mean by "trying to start a db project" but this is my guess:
https://www.sqlite.org/cvstrac/wiki?p=HowToCompileWithVsNet
Make a .DEF file
A .def file should be placed in the project directory. Get the def file by ...
0
That sounds like a problem with the shared drive arrangement, rather then one specific to sqlite. It would be worth stating which virtualisation method you are using as people may know if there are common problems with it.
The slower run from a resourse within the VM may be due to I/O overhead from the virt method, or extra IO contention because the input ...
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Assuming that you want a SQL-only solution and your table is defined as:
CREATE TABLE measurements (
pk INTEGER PRIMARY KEY,
timestamp INTEGER NOT NULL,
value TEXT NOT NULL,
sensor_id INTEGER);
then create the following views:
CREATE VIEW vw_measurements AS
SELECT pk, timestamp, value, sensor_id,
3600*ROUND((timestamp+1800)/3600) AS hour,
...
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The sqlite_master table holds all info on tables and indexes of the database. Assuming the existing table is called oldtable, you can retrieve the table definition from sqlite_master as:
SELECT sql
FROM sqlite_master
WHERE type = 'table' AND name = 'oldtable';
In the retrieved sql field, replace the oldtable with newtable and run the SQL statement against ...
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For every line, you check that there are no lines in the previous 2 seconds with value smaller than 0.9 (therefore they all are greater than 0.9).
select * from table outer_table where value > 0.9 and not exists (
select * from table where value <= 0.9 and (outer_table.time - time) <= 2
)
2
Your query is correct and works fine in other DBMS (SQL-Server, Postgres, Oracle, MySQL). In SQLite, it appears there is a bug, possibly due to the correlated subquery and/or the grouping in both the main and the sub query. Here is another way to write the query:
SELECT id, COUNT(*) AS count1
FROM Likes
GROUP BY id
HAVING COUNT(*) =
( SELECT COUNT(*) ...
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