New answers tagged subquery
I guess this is want you want: For every player, find his team and calculate the sum of kills and golds for all the matches of that team: SELECT p.player_id, SUM(t.kills) AS total_kills_in_team, SUM(t.total_gold) AS total_gold_in_team FROM ( SELECT player_id, team_id, match_id FROM lcs_result GROUP BY ...
try this: SELECT * FROM test_table where aa >= all (SELECT aa FROM test_table);
Try like SELECT MAX(A.count_supplier), A.id FROM ( SELECT supplier_id as id, COUNT(*) AS count_supplier FROM library.lms_book_details GROUP BY supplier_id ) A GROUP BY A.id; Alias inner COUNT(*) as something different than COUNT as it is good practice to not use it as alias , As i have used count_supplier.
SELECT MAX(COUNT), A.id FROM ( SELECT supplier_id as id, COUNT(*) AS count FROM library.lms_book_details GROUP BY supplier_id ) as A GROUP BY A.id;
Example : If query SELECT id FROM test_table; returns output like 10 20 30 Now use sub query to find Maximum do like SELECT MAX(a.id) FROM (SELECT id FROM test_table) a;
I suggest to use a trigram index provided by the additional module pg_trgm. Combine that with the length of the string to get a valid pre-selection. Drop the columns T4,T16 and T64 (faster in a single statement), and run VACUUM FULL or CLUSTER. Install pg_trgm. Details here: Full Text Search With PostgreSQL Create a GiST index on tl and length(tl) There ...
With queries like this is it often more efficient to perform a LEFT OUTER JOIN instead of the NOT EXISTS style check, it often implies a full index scan (or table scan without the right indexes in place) but with many rows in the main table(s) this is less expensive than the large number of index seeks (one on the reference table for each row returned from ...
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