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Dec 1, 2016 at 9:23 vote accept Gareth
Nov 21, 2016 at 20:06 answer added Rick James timeline score: 1
Nov 21, 2016 at 13:35 comment added Andriy M Feel free to answer with your own solution if/when you've figured out one.
Nov 21, 2016 at 13:15 comment added Gareth @AndriyM Yes, that's essentially what I want to do. I suppose by best I mean the least hacky way of doing it. Having read your simpler way of expressing it, it's occurred to me that what I need to do is take the day and month of date S and append the year of date C - if this new date is before date C return it, otherwise return the day and month of date S with the year of date C - 1.
Nov 21, 2016 at 12:25 comment added Andriy M In other words, given dates S and C, you want to subtract one year from date S iteratively until it falls before date C (unless it's already before date C), correct? On a different note, what do you mean by "best" in "what would be the best way…"?
Nov 21, 2016 at 10:20 review First posts
Nov 21, 2016 at 12:25
Nov 21, 2016 at 10:19 history asked Gareth CC BY-SA 3.0