4

I have following request:

SELECT XMLAGG(data) FROM
(SELECT XMLELEMENT(name item, XMLFOREST(
   title,
   body as description,
   date_created as date,
   'http://example.com/news'||id as link 
)) AS data FROM NEWS) AS smthng;

The issue is that body is actually XML itself, so the question is - How can I escape XML field (changing < to &lt; > to &gt; etc.) in this query?

1 Answer 1

1

The naive approach would be to wrap your query around another SELECT and use replace.

SELECT replace(
    (SELECT XMLAGG(data) FROM
         (SELECT XMLELEMENT(name item, XMLFOREST(
          title,
          body as description,
          date_created as date,
          'http://example.com/news'||id as link 
         )
     ) AS data FROM NEWS) AS smthng)::text, '<', '&lt;')

And do the same for >. A easier and more elgant mthod would be to to it with the language that should deliver/process/... the XML.

1
  • I can write something like ` SELECT replace(XMLSERIALIZE(CONTENT body as VARCHAR),'"','&quot;') from news; ` and so on. This is quite naive as well. It's a pity if there is no more handy language, since anything else related to XML output fits just perfect to me.
    – shabunc
    Jan 13, 2012 at 15:49

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