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enter image description hereI want to select the soundex value S225  for the two names

This is what iried using this query but am not getting the exact result.

I got the output with the same name and same soundex value, but I want the result which has similar name and same soundex value.

Can anyone help me to do this?

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  • Please give some examples that you'd like to find. How similar is similar?
    – dezso
    Jul 9, 2015 at 11:06
  • 1
    And please do not post SQL statements as screen shots. Show the statements as formatted text.
    – user1822
    Jul 9, 2015 at 11:14

1 Answer 1

2

You can use a window function for this:

select *
from (
   select name, 
          count(*) over (partition by soundex(name)) as cnt
   from poi
) t
where cnt > 1;
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  • It Works...................... Thank u so much ...a_horse_with_no_name. then, what does the variable 't' stands for in that query? Jul 9, 2015 at 11:46
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    @MohamedAshrafAliB it's not a variable but a mandatory table alias for a subquery.
    – dezso
    Jul 9, 2015 at 11:59
  • @a_horse_with_no_name Jul 22, 2015 at 6:26

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