You may not be able to see the object in the ALL_% tables if you don't have any grants on the object itself, so check in the DBA_OBJECTS table (you will need grants/an appropriately granted user to do this):
select *
from DBA_OBJECTS
where object_name = 'COT_NTN_PI_V';
If that doesn't produce any output you can check in the raw Oracle data dictionary tables with this query:
select u.name as owner, o.name as object_name,
decode(o.type#, 0, 'NEXT OBJECT', 1, 'INDEX', 2, 'TABLE', 3, 'CLUSTER',
4, 'VIEW', 5, 'SYNONYM', 6, 'SEQUENCE',
7, 'PROCEDURE', 8, 'FUNCTION', 9, 'PACKAGE',
11, 'PACKAGE BODY', 12, 'TRIGGER',
13, 'TYPE', 14, 'TYPE BODY',
19, 'TABLE PARTITION', 20, 'INDEX PARTITION', 21, 'LOB',
22, 'LIBRARY', 23, 'DIRECTORY', 24, 'QUEUE',
28, 'JAVA SOURCE', 29, 'JAVA CLASS', 30, 'JAVA RESOURCE',
32, 'INDEXTYPE', 33, 'OPERATOR',
34, 'TABLE SUBPARTITION', 35, 'INDEX SUBPARTITION',
39, 'LOB PARTITION', 40, 'LOB SUBPARTITION',
43, 'DIMENSION',
44, 'CONTEXT', 47, 'RESOURCE PLAN',
48, 'CONSUMER GROUP',
51, 'SUBSCRIPTION', 52, 'LOCATION', 56, 'JAVA DATA', 'UNKNOWN') as type,
o.ctime, o.mtime,
to_char(o.stime, 'YYYY-MM-DD:HH24:MI:SS'),
decode(o.status, 0, 'N/A', 1, 'VALID', 'INVALID') as status
from sys.obj$ o, sys.user$ u
where o.owner# = u.user#
and o.linkname is null
and (o.type# not in (1 , 10) or
(o.type# = 1 and 1 = (select 1
from sys.ind$ i
where i.obj# = o.obj#
and i.type# in (1, 2, 3, 4, 6, 7, 9))))
and o.name = 'COT_NTN_PI_V';