I have the following structure:

Table R     Table RZ (n-m)    Table Z
-------     -----------------  ---------
R1          R1 | Z1           Z1 | "A"
R2          R1 | Z2           Z2 | "B"
R3          R2 | Z1           Z3 | "C"
R4          R2 | Z3           Z4 | "D"
...         R3 | Z1             ... 
...         R3 | Z2             ... 
...         R3 | Z4             ... 

(I left out some additional complications and further joins to simplify)

I need to query all rows from "R" with some of the columns or "R" including a column in the result that has the concatenated "Name" column of table "Z".

Here is a sample following the given table contents above:

ID of R | Name of Z
R1      | "A,B"
R2      | "A,C"
R3      | "A,B,D"

So far a scalar function was in place, used by every row of R, re-querying the R- RZ-Z join again, concatenating and returning the names, but I figured this is very slow.

I tried FOR XML, but I can't manage to combine the XML result delivering the string I want with the rest of the columns required from table R.

What is the best way to solve this?

  • For table Z : the second column have saved also the character "A" - double quotes ? or just simple value like A – Sabin Bio Dec 6 '16 at 18:36
  • this is just sample data - simple varchar, the quotes just indcate this is some text. – Magier Dec 7 '16 at 8:29

Try with CROSS APPLY , like this:

    R.idR AS [idR]
    ,'"'+ REPLACE(STUFF(CA.NameOfZ,1,1,''),'"','') + '"' AS NameOfZ
    @tableR AS R
    (  SELECT
            @tableZ AS Z
            INNER JOIN @tableRZ AS RZ
            ON  Z.colZ = RZ.colZ
            R.idR = RZ.idR
        FOR XML PATH('')
    CA.NameOfZ IS NOT NULL  


idR  NameOfZ
R1   "A,B"
R2   "A,C"
R3   "A,B,C,D"
| improve this answer | |
  • 1
    PERFECT SOLUTION! – Magier Dec 7 '16 at 8:43

Something like this should work:

select R.ID,
     FROM Z
     FOR XML PATH ('')), 1, 2, ''))  
from R  
inner join RZ on R.ID = RZ.RID
| improve this answer | |
  • This does not work as needed. It delivers separate Rows for each row for each RZ entry instead of concatenation of the Z.Name column values for each unique R item. So it's result is similar to a simple join. – Magier Dec 7 '16 at 8:38

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