For completeness, another way to approach this problem is to use OUTER APPLY. We can add an OUTER APPLY
operator for each distinct value that we need to find. This is similar in concept to ypercube's recursive approach, but effectively has the recursion written out by hand. One advantage is that we're able to use TOP
in the derived tables instead of the ROW_NUMBER()
workaround. One big disadvantage is the query text gets longer as N
increases.
Here is one implementation for the query against the heap:
SELECT VAL
FROM (
SELECT t1.VAL VAL1, t2.VAL VAL2, t3.VAL VAL3, t4.VAL VAL4, t5.VAL VAL5, t6.VAL VAL6, t7.VAL VAL7, t8.VAL VAL8, t9.VAL VAL9, t10.VAL VAL10
FROM
(
SELECT TOP 1 VAL FROM X_10_DISTINCT_HEAP
) t1
OUTER APPLY
(
SELECT TOP 1 VAL FROM X_10_DISTINCT_HEAP t2 WHERE t2.VAL NOT IN (t1.VAL)
) t2
OUTER APPLY
(
SELECT TOP 1 VAL FROM X_10_DISTINCT_HEAP t3 WHERE t3.VAL NOT IN (t1.VAL, t2.VAL)
) t3
OUTER APPLY
(
SELECT TOP 1 VAL FROM X_10_DISTINCT_HEAP t4 WHERE t4.VAL NOT IN (t1.VAL, t2.VAL, t3.VAL)
) t4
OUTER APPLY
(
SELECT TOP 1 VAL FROM X_10_DISTINCT_HEAP t5 WHERE t5.VAL NOT IN (t1.VAL, t2.VAL, t3.VAL, t4.VAL)
) t5
OUTER APPLY
(
SELECT TOP 1 VAL FROM X_10_DISTINCT_HEAP t6 WHERE t6.VAL NOT IN (t1.VAL, t2.VAL, t3.VAL, t4.VAL, t5.VAL)
) t6
OUTER APPLY
(
SELECT TOP 1 VAL FROM X_10_DISTINCT_HEAP t7 WHERE t7.VAL NOT IN (t1.VAL, t2.VAL, t3.VAL, t4.VAL, t5.VAL, t6.VAL)
) t7
OUTER APPLY
(
SELECT TOP 1 VAL FROM X_10_DISTINCT_HEAP t8 WHERE t8.VAL NOT IN (t1.VAL, t2.VAL, t3.VAL, t4.VAL, t5.VAL, t6.VAL, t7.VAL)
) t8
OUTER APPLY
(
SELECT TOP 1 VAL FROM X_10_DISTINCT_HEAP t9 WHERE t9.VAL NOT IN (t1.VAL, t2.VAL, t3.VAL, t4.VAL, t5.VAL, t6.VAL, t7.VAL, t8.VAL)
) t9
OUTER APPLY
(
SELECT TOP 1 VAL FROM X_10_DISTINCT_HEAP t10 WHERE t10.VAL NOT IN (t1.VAL, t2.VAL, t3.VAL, t4.VAL, t5.VAL, t6.VAL, t7.VAL, t8.VAL, t9.VAL)
) t10
) t
UNPIVOT
(
VAL FOR VALS IN (VAL1, VAL2, VAL3, VAL4, VAL5, VAL6, VAL7, VAL8, VAL9, VAL10)
) AS upvt;
Here is the actual query plan for the above query. On my machine this query completes in 713 ms with 625 ms of CPU time and 12605 logical reads. We get a new distinct value every 100k rows so I would expect this query to scan around 900000 * 10 * 0.5 = 4500000 rows. In theory this query should do five times the logical reads of this query from the other answer:
DECLARE @j INT = 10;
SELECT DISTINCT TOP (@j) VAL
FROM X_10_DISTINCT_HEAP
OPTION (MAXDOP 1, OPTIMIZE FOR (@j = 1));
That query did 2537 logical reads. 2537 * 5 = 12685 which is pretty close to 12605.
For the table with the clustered index we can do better. This is because we can pass in the last clustered key value into the derived table to avoid scanning the same rows twice. One implementation:
SELECT VAL
FROM (
SELECT t1.VAL VAL1, t2.VAL VAL2, t3.VAL VAL3, t4.VAL VAL4, t5.VAL VAL5, t6.VAL VAL6, t7.VAL VAL7, t8.VAL VAL8, t9.VAL VAL9, t10.VAL VAL10
FROM
(
SELECT TOP 1 PK, VAL FROM X_10_DISTINCT_CI
) t1
OUTER APPLY
(
SELECT TOP 1 PK, VAL FROM X_10_DISTINCT_CI t2 WHERE PK > t1.PK AND t2.VAL NOT IN (t1.VAL)
) t2
OUTER APPLY
(
SELECT TOP 1 PK, VAL FROM X_10_DISTINCT_CI t3 WHERE PK > t2.PK AND t3.VAL NOT IN (t1.VAL, t2.VAL)
) t3
OUTER APPLY
(
SELECT TOP 1 PK, VAL FROM X_10_DISTINCT_CI t4 WHERE PK > t3.PK AND t4.VAL NOT IN (t1.VAL, t2.VAL, t3.VAL)
) t4
OUTER APPLY
(
SELECT TOP 1 PK, VAL FROM X_10_DISTINCT_CI t5 WHERE PK > t4.PK AND t5.VAL NOT IN (t1.VAL, t2.VAL, t3.VAL, t4.VAL)
) t5
OUTER APPLY
(
SELECT TOP 1 PK, VAL FROM X_10_DISTINCT_CI t6 WHERE PK > t5.PK AND t6.VAL NOT IN (t1.VAL, t2.VAL, t3.VAL, t4.VAL, t5.VAL)
) t6
OUTER APPLY
(
SELECT TOP 1 PK, VAL FROM X_10_DISTINCT_CI t7 WHERE PK > t6.PK AND t7.VAL NOT IN (t1.VAL, t2.VAL, t3.VAL, t4.VAL, t5.VAL, t6.VAL)
) t7
OUTER APPLY
(
SELECT TOP 1 PK, VAL FROM X_10_DISTINCT_CI t8 WHERE PK > t7.PK AND t8.VAL NOT IN (t1.VAL, t2.VAL, t3.VAL, t4.VAL, t5.VAL, t6.VAL, t7.VAL)
) t8
OUTER APPLY
(
SELECT TOP 1 PK, VAL FROM X_10_DISTINCT_CI t9 WHERE PK > t8.PK AND t9.VAL NOT IN (t1.VAL, t2.VAL, t3.VAL, t4.VAL, t5.VAL, t6.VAL, t7.VAL, t8.VAL)
) t9
OUTER APPLY
(
SELECT TOP 1 PK, VAL FROM X_10_DISTINCT_CI t10 WHERE PK > t9.PK AND t10.VAL NOT IN (t1.VAL, t2.VAL, t3.VAL, t4.VAL, t5.VAL, t6.VAL, t7.VAL, t8.VAL, t9.VAL)
) t10
) t
UNPIVOT
(
VAL FOR VALS IN (VAL1, VAL2, VAL3, VAL4, VAL5, VAL6, VAL7, VAL8, VAL9, VAL10)
) AS upvt;
Here is the actual query plan for the above query. On my machine this query completes in 154 ms with 140 ms of CPU time and 3203 logical reads. This seemed to run a bit faster than the OPTIMIZE FOR
query against the clustered index table. I wasn't expecting that so I tried to measure the performance more carefully. My methodology was to run each query ten times without result sets and to look at the aggregate numbers from sys.dm_exec_sessions
and sys.dm_exec_session_wait_stats
. Session 56 was the APPLY
query and session 63 was the OPTIMIZE FOR
query.
Output of sys.dm_exec_sessions
:
╔════════════╦══════════╦════════════════════╦═══════════════╗
║ session_id ║ cpu_time ║ total_elapsed_time ║ logical_reads ║
╠════════════╬══════════╬════════════════════╬═══════════════╣
║ 56 ║ 1360 ║ 1373 ║ 32030 ║
║ 63 ║ 2094 ║ 2091 ║ 30400 ║
╚════════════╩══════════╩════════════════════╩═══════════════╝
There appears to be a clear advantage in cpu_time and elapsed_time for the APPLY
query.
Output of sys.dm_exec_session_wait_stats
:
╔════════════╦════════════════════════════════╦═════════════════════╦══════════════╦══════════════════╦═════════════════════╗
║ session_id ║ wait_type ║ waiting_tasks_count ║ wait_time_ms ║ max_wait_time_ms ║ signal_wait_time_ms ║
╠════════════╬════════════════════════════════╬═════════════════════╬══════════════╬══════════════════╬═════════════════════╣
║ 56 ║ SOS_SCHEDULER_YIELD ║ 340 ║ 0 ║ 0 ║ 0 ║
║ 56 ║ MEMORY_ALLOCATION_EXT ║ 38 ║ 0 ║ 0 ║ 0 ║
║ 63 ║ SOS_SCHEDULER_YIELD ║ 518 ║ 0 ║ 0 ║ 0 ║
║ 63 ║ MEMORY_ALLOCATION_EXT ║ 98 ║ 0 ║ 0 ║ 0 ║
║ 63 ║ RESERVED_MEMORY_ALLOCATION_EXT ║ 400 ║ 0 ║ 0 ║ 0 ║
╚════════════╩════════════════════════════════╩═════════════════════╩══════════════╩══════════════════╩═════════════════════╝
The OPTIMIZE FOR
query has an additional wait type, RESERVED_MEMORY_ALLOCATION_EXT. I don't exactly know what this means. It may just be a measurement of the overhead in the hash match (flow distinct) operator. In any case, perhaps it's not worth worrying about a difference of 70 ms in CPU time.