I know the column order in a compound index matters if you want to query by a subset of the indexed-columns, but if you're query specifies values for all the indexed columns, is there any performance benefit to having a high-cardinality column earlier than a low-cardinality column? I vaguely remember reading something that suggested that was the case because it narrows down the result set quicker, but I can't find anything to back that up now.

I'm using MySQL w/ InnoDB. InnoDB uses clustered indexes, which might be relevant to my question, but I think it only does so for primary keys, which my index is not. The table looks something like this:

CREATE TABLE `my_table` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `ref_a_id` int(10) unsigned NOT NULL,
  `ref_b_id` int(10) unsigned NOT NULL,
  `is_active` tinyint(1) DEFAULT '1',
  PRIMARY KEY (`id`),
  UNIQUE KEY `index_my_table_on_ref_a_ref_b_is_active` (`ref_a_id`, `ref_b_id`, `is_active`)

In relation to my question, imagine ref_a_id has a higher cardinality than ref_b_id.

1 Answer 1


It is an old wives' tale that cardinality matters.

INDEX(a,b) and INDEX(b,a) perform virtually identically when in a BTree. The depth of the BTree is the same.

What does matter is that both columns are searched with =, as in WHERE a=12 AND b=45.

The PRIMARY KEY in InnoDB is a BTree, and so is each secondary index. The only difference is what else is in the leaf nodes. The PK's leaf nodes contains all columns; a secondary index's leaf nodes contains the columns of the PK.

In InnoDB (not in some competing products), the PK is, by definition, clustered and UNIQUE.

As for your table,...

Are you allowing to rows for each ref_a--ref_b combo? One 'active', one not? This seems unlikely.

Why have id at all? Why not promote the UNIQUE key to be the PK?

Is is_active ever NULL?

See my tips on many:many mapping tables.

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