I have innodb_buffer_pool_size=100GB;

show table status where name='test_tb'\G                                                                          


    Data_length: 4686086144
Max_data_length: 0
   Index_length: 5107564544

seems index uses 5GB memory.

ANALYZE table test_tb;
sum(stat_value) pages,
  sum(stat_value) * @@innodb_page_size /1024/1024 "size(MB)"
  table_name = 'test_tb'
  AND database_name = 'test_dbs'
  AND stat_description = 'Number of pages in the index'

| pages  | index_name        | size(MB)      |
| 286016 | PRIMARY           | 4469.00000000 |
| 150014 | test_key1         | 2343.96875000 |
| 161727 | test_key2         | 2526.98437500 |

its 8GB.

So which one is accurate?

  • The size of the "Primary"-index equals your data_length, the other 2 indexes will sum up to index_length. InnoDB stores all data in btree-structures (indexes).
    – Solarflare
    Commented Aug 24, 2017 at 10:34

1 Answer 1


Both are correct; both say the same values. (Don't divide by 1024*1024; it will be a little more obvious.)

In InnoDB, the PRIMARY KEY is "clustered" with the data. That is, they are both in the same BTree structure. The PK provides the order; the data provides the content.

In your table, the data is ~4GB, including the PK and BTree overhead; the two indexes are in two separate BTrees, adding up to about 5GB.

  • So the memory allocation in innodb_buffer_pool_size of this table is roughly 9GB? What' in separate index btree? for example, the test_key1 index bree. I suppose the data of the columns of test_key1, and pointer to PK?
    – Sato
    Commented Aug 25, 2017 at 0:37
  • Up to 9GB of the buffer_pool will be used for these 3 BTrees. It is a "cache", allocated 16KB at a time, so it may or may not every actually consume 9GB. The leaf nodes of a secondary index contain the PK values.
    – Rick James
    Commented Aug 25, 2017 at 4:36

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