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I have a table which stores data about an inspection. Inspections are carried out in a particular company belonging to an industry, located in a region. the inspections table has the industry_id field referencing the industry table and the region_id field referencing the region table.

Both industry and region tables have id and name fields.

running this query:

SELECT i.name industry, r.name region, COUNT(*) 
FROM labour_inspections l
left join company_industries i on l.industry_id=i.id 
left join regions r on l.region_id=r.id 
where i.name != 'NULL' and r.name != 'NULL' 
GROUP BY i.name and r.name

gives me the results i need but not in the way i want it for this view.Desired report view

I achieved that by writing separate queries and putting the results together with PHP. It is not elegant and I am concerned about performance.

Is there a way I can achieve the view in the image with a single query? Thank you all in advance

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  • Replace LEFT JOIN with INNER JOIN and remove the whole WHERE clause.
    – Akina
    Commented Aug 29, 2018 at 12:45
  • Is there a way I can achieve the view in the image with a single query? MySQL knows nothing about PIVOT. Transform your data on the client side (using its report component, for example) or emulate pivot with a code in a stored procedure form (you must understand it is not easy to create such procedure).
    – Akina
    Commented Aug 29, 2018 at 12:48

1 Answer 1

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name != 'NULL'

That assumes that name can be the 4-letter string 'NULL'. If, in reality, it can be the special value NULL, then do this:

name IS NOT NULL

Please provide SHOW CREATE TABLE for each table, plus a small amount of representative data including some nulls.

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