I have a table with the below structure and data:

create table employee (id int, name varchar, father_name varchar);
insert into employee values(1, 'John', 'Alex'),(2, 'Simi', 'Expatri'),(3, 
'John', 'Alex'),(4, 'Hezad', 'Ambrose'),(5, 'John', 'Alex'), (6, 'Simi', 
'Expatri'), (7, 'Hezad', 'Ambrose'), (8, 'John', 'Reman'), (9, 'Komal', 

Now I want to fetch those records whose two columns name and father_name match each other.
The desired result would be as following:

id    |    name    |    father_name
1     |    John    |    Alex  
3     |    John    |    Alex  
5     |    John    |    Alex  
2     |    Simi    |    Expatri  
6     |    Simi    |    Expatri  
4     |    Hezad   |    Ambrose  
7     |    Hezad   |    Ambrose  

Any help is appreciated in advance.


Ordering by name and father_name is the first step, but I assume you don't want records where no other matching records are found. This would work:

select e1.id, e1.name, e1.father_name
  from employee as e1
  inner join employee as e2
    on e1.name = e2.name
   and e1.father_name = e2.father_name
   and e1.id != e2.id
  group by e1.id, e1.name, e1.father_name
  order by e1.name, e1.father_name

Here is a working demo.

|improve this answer|||||
select id, name, father_name
  from employee
  where (name, father_name) in (
     select name, father_name
       from employee
       group by name, father_name
       having count(*) > 1
  order by father_name, name
|improve this answer|||||
  • 1
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