I have a table named inward_outward where I want to group by name and show total entries, total inward count and total outward count.

This is what I have so far


    ($con," SELECT name from inward_outward,
    ( SELECT  count(status) from inward_outward WHERE status ='inward' )As count_1,
    ( SELECT count(status) from inward_outward WHERE status ='out' )As count_2,
    ( SELECT count(status) from inward_outward WHERE 1 )As count_3
    GROUP BY name")

    or die(mysqli_error($con));
      while ($row=mysqli_fetch_array($query)){

    echo "<tr>";    
echo "<td>" . $row['inspector_name'] . "</td>";
echo "<td>" . $row['count_1'] . "</td>";
echo "<td>" . $row['count_2'] . "</td>";
echo "<td>" . $row['count_3'] . "</td>";
echo "</tr>";

I want to take count from status column where status = 'inward' and status = 'out' then group by name

  • I have moved your comment into the body post. – jcolebrand Oct 18 '18 at 19:29

I'm unclear on what you want, but I think this will come closer:

SELECT name,
       SUM(status = 'inward') AS in_ct,
       SUM(status = 'out')    AS out_ct,
       COUNT(*)               AS both
    FROM inward_outward
    GROUP BY name;


  • SUM(boolean-expr) counts the number of TRUEs
  • COUNT(*) counts rows; COUNT(x) counts the number of non-null x
  • GROUP BY should list all the non-aggregates, and nothing else.
  • Subqueries are not needed in this case.
  • FROM must come after the items selected.
  • Thank you for your help. It is the correct . It worked fine. – Mangesh Oct 19 '18 at 13:50

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