I have a table like the following

   ID                created    sent    type
0001463583000051783  31-JUL-12  1   270
0081289563000051788  01-AUG-12  1   270
0081289563000051792  01-AUG-12  1   270
0081289563000051791  01-AUG-12  1   270
0081289563000051806  01-AUG-12  1   270
0001421999000051824  06-AUG-12  1   270
0001421999000051826  06-AUG-12  1   270
0001464485000051828  06-AUG-12  1   270
0082162128000051862  09-AUG-12  2   278
0082162128000051861  09-AUG-12  2   278
0022409222082910259  09-AUG-12  3   278

I would like to have the following for output

created     Count
31-JUL-12   1
01-AUG-12   4
06-AUG-12   3
09-AUG-12   3

How hard would it be to accomplish this using SQL Developer on Oracle 10g?

I have tried several queries to generate such a table and in the end it does not group the count by date, just gives me a '1' for the count when we average 5000-10000 transactions daily. I'm probably overcomplicating it. But I would like something simple where I can pull the amount of transactions on a daily basis within a date range.

  • How about you post the queries you've tried that didn't work? I wouldn't want to suggest a query only for you to reply that you've already tried it. Oct 30, 2012 at 20:52

1 Answer 1


Unless I am missing something, your query would be something like this:

select created, count(*) CreatedCount
from yourtable
group by created
order by created;

See SQL Fiddle with Demo

Or if you have a time associated with the date, you can use TRUNC:

select trunc(created), count(*) CreatedCount
from yourtable
group by trunc(created)
order by trunc(created);

See SQL Fiddle with Demo

  • 2
    I'm guessing the "created" dates also have a time part, and some form of truncing would help the OP.
    – Mat
    Oct 31, 2012 at 6:52
  • @Mat good point, updated with query that includes trunc
    – Taryn
    Oct 31, 2012 at 10:00
  • Nice solution! Didnt realize there is a trunc function for Oracle.
    – Thyag
    Aug 29, 2019 at 21:32

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