I have a table with column type as json.

select request_id,cast(job_info as varchar)  from requests_table where cast(job_id as varchar) like '%4665-b583-3b92218db8ce%';

Here job_info and job_id are the json type column.

It yield me data like this:

          request_id   |                 job_info
 f373085d-0124a161b2d7 | ["test-cluster", "test-cluster-id-11111"]
(1 row)

I am expecting job_info data should get retrieved as two separate column.


1 Answer 1


You can extract each array element using the->> operator:

select request_id,
       job_info ->> 0 as cluster_1, 
       job_info ->> 1 as cluster_2
from requests_table 
where cast(job_id as varchar) like '%4665-b583-3b92218db8ce%'
  • Thanks.. Perfect!. I was doing something like this. Thanks again Nov 19, 2020 at 13:08
  • what if my job_id has multiple values like job_info and I have to look specific value using where clause.. let me know if it has to be another question. Thanks Nov 19, 2020 at 13:39
  • 1
    yes, please ask a new question.
    – user1822
    Nov 19, 2020 at 14:00

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