I have generated an EXPDAT.DMP file of an Oracle database with the command:

exp userid=usr/pass@db owner=own rows=n compress=n

I then ran the following command to generate a file containing the 'Create Table...' statements:

imp userid=usr/pass@db full=y indexfile=output.sql

This is great for the Create Table statements, but I also want the Create Procedure / Create Function / Create View source code. I can see them there in the .DMP file, but I haven't found a way to extract them.

Is it possible to extract this information from the EXPDAT.DMP file? Or will I need to use another method?

The purpose is to have the source exportable to files that can be source-controlled.

3 Answers 3


If you've got access to the original database, I'd go with DBMS_METADATA.GET_DDL.

You can script it with UTL_FILE so that it goes through each object (from USER_OBJECTS), uses the name and type to extract the object then write it to a file that has the appropriate naming convention.

It will be a lot cleaner than trying to split a single file.

  • Can you recommend a good example/tutorial for DBMS_METADATA.GET_DDL? I'm mostly finding 'spool... select dbms_metadata.get_dll() from dual; spool off' through Google. Is that about right? May 19, 2011 at 2:28
  • 1
    First place I look for tutorials is oracle-base.com. oracle-base.com/articles/9i/MetadataAPI.php
    – Gary
    May 20, 2011 at 10:20

Use the SHOW parameter to see the DDL:

imp userid=usr/pass@db full=y show=y log=imp.log

If you can use datapump(expdp,impdp) utility ,instead of traditional export , then sqlfile command can be used.

-- Take expdp

 expdp dumpfile=full.dmp logfile=full.log directory=EXP_DIR schemas=SCOTT

-- below impdp wont import, it will just generated all the object code in fullcode.sql file

impdp dumpfile=full.dmp logfile=full.log directory=EXP_DIR schemas=SCOTT content=metadata_only sqlfile=fullcode.sql

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