SQL> desc tab1
 Name                                      Null?    Type
 ----------------------------------------- -------- ----------------------------
 ID                                                 NUMBER
 NAME                                               VARCHAR2(1000)

SQL> select * from tab1;

        ID NAME
---------- ---------------
         1 a
         2 b
         3 c

SQL> select * from tab1 where id > AVG(id);
select * from tab1 where id > AVG(id)
ERROR at line 1:
ORA-00934: group function is not allowed here


The error is very clear and says that this cannot be done. But I don't see why. The query makes perfect sense:

select all rows from tab1 whose id value is greater than the average


AVG and other aggregate functions work on sets of data. The WHERE cause does not have access to the entire set, only to data for the row it is operating on. If you created your own AVG function (as a normal function and not a custom aggregate function) it would only be passed one ID value when called from the WHERE clause not the entire set of ID values.

Mezmo's solution will give you your expected results, but if you want to avoid two full table scans (assuming no indexes) you can use a windowing function like this:

SELECT * FROM (SELECT AVG(id) OVER () avgid, t.* FROM tab1 t) WHERE id > avgid;

Well, the short answer is "'Cause Larry says so." ;) but you can do it with a nested select:

select * from tab1 where id > (select avg(id) from tab1)


  • 5
    This wasn't "Larry's decision", this is defined in the SQL standard. Jun 28 '11 at 21:41

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