I want to list all the partitions created by dynamic triggers in PostgreSQL 9.1.
I was able to generate a count of partitions using this related answer by Frank Heikens.

I have a table foo with an insert trigger that creates foo_1, foo_2 etc. dynamically. The partition for insert is chosen based on the primary key id, a range based partitioning.

Is it possible to display all partitions currently in place for table foo?


2 Answers 2


Use the first query from the answer you linked and add a simple WHERE clause to get the partitions of a single table:

    nmsp_parent.nspname AS parent_schema,
    parent.relname      AS parent,
    nmsp_child.nspname  AS child_schema,
    child.relname       AS child
FROM pg_inherits
    JOIN pg_class parent            ON pg_inherits.inhparent = parent.oid
    JOIN pg_class child             ON pg_inherits.inhrelid   = child.oid
    JOIN pg_namespace nmsp_parent   ON nmsp_parent.oid  = parent.relnamespace
    JOIN pg_namespace nmsp_child    ON nmsp_child.oid   = child.relnamespace
WHERE parent.relname='parent_table_name';
  • Is there something specific to partitions here or does this just give all tables that inherit from the parent?
    – Andrew
    Nov 28, 2022 at 22:32
  • @Andrew in the past 10 years Postgres has seen a lot of progress in partitioning. I'm not sure without proper checking this answer is still useful nowadays... However, your question is a good one, and I think you are right assuming that 'plain' inheritance will be shown in the query output.
    – dezso
    Mar 23 at 14:26

Use the object identifier type regclass for a very simple query:

SELECT inhrelid::regclass AS child -- optionally cast to text
FROM   pg_catalog.pg_inherits
WHERE  inhparent = 'my_schema.foo'::regclass;

Lists all child tables of given parent table parent_schema.foo. Schema-qualification is optional, the search_path decides visibility if missing.

Similarly, returned table names are schema-qualified and escaped automatically where necessary. Safe, fast and simple.

The solution also works for declarative partitioning in Postgres 10 or later because, quoting the manual:

Individual partitions are linked to the partitioned table with inheritance behind-the-scenes;

Aside, to display the source table for any row retrieved from any table:

SELECT tableoid::regclass AS source, *
FROM   my_schema.foo
WHERE  <some_condition>;
  • Thanks! This works on Postgres 12.7.10. Sep 22, 2021 at 7:19

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