I'm using PostgreSQL 9.1 with a Ruby on Rails application.
I'm trying to list the last version of each "charge" (in my history table : hist_version_charges) belonging to the same project id (proj_sous_projet_id = 2).
This makes me use the max() aggregate function and apply the result to a JOIN function on the same table as PostgreSQL does not authorize to use the columns in the SELECT clause if they do not appears in the GROUP BY clause, ALTHOUGH using a max() mean obviously I'm interested to the row containing the max values!
This is my query :
SELECT h_v_charges.*, max(last_v.version) as lv FROM hist_versions_charges h_v_charges JOIN hist_versions_charges last_v ON h_v_charges.version = lv AND h_v_charges.proj_charge_id = last_v.proj_charge_id GROUP BY last_v.proj_sous_projet_id, last_v.proj_charge_id HAVING last_v.proj_sous_projet_id = 2 ORDER BY h_v_charges.proj_charge_id ASC;
The error message I got :
ERROR: column "lv" does not exist LINE 1: ..._versions_charges last_v ON h_v_charges.version = lv AND h_v... ^ ********** Error ********** ERROR: column "lv" does not exist SQL state: 42703 Character: 147
I also tried with "last_v.lv" but the error remains the same.
If anybody got an idea about what's wrong, she is more than welcome.
=== UPDATE ===
According to * a_horse_with_no_name * and Colin 't Hart answers, I finally ended up with the following query :
SELECT * FROM ( SELECT *, max(version) OVER (PARTITION BY proj_charge_id) AS lv FROM hist_versions_charges WHERE proj_sous_projet_id = 2) AS hv WHERE hv.lv = hv.version ORDER BY hv.proj_charge_id ASC;
It is slightly quicker with a single ORDER BY.
I tried as well the query with a WITH clause. Though "nicer", it creates additional processing charge. As I know I will not re-used in the future the sub-query twice or more in the same main query, I'm fine with using a simple sub-query.
Thanks anyway to *a_horse_with_no_name* and Colin 't Hart. I learned many things !
SELECTlist) in the
FROMclause (actually the
ONpart but that's still in the FROM clause)!