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I have 2 SQL Server 2008 instances installed on the same server. They have same table structures with same data. I have a stored procedure deployed on both of them. The stored procedure performs differently on them. It takes 5 seconds on one instance and 50 seconds on the other to execute the procedure. I think the possible reasons for this are: index fragmentation, outdated statistics. I defragmented the indexes and updated the statistics but still no luck. Any ideas on this issue?

Thanks

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    Add the query plans please. And difference in versions via SELECT @@VERSION?
    – gbn
    Commented Sep 29, 2011 at 12:41
  • Do you have the user and TempDB databases on the same/similar drives? If one is on a slower drive/RAID it's possible to have differences. We still need the execution plans for both situations in order to be able to say anything.
    – Marian
    Commented Sep 29, 2011 at 13:18

3 Answers 3

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Are the two instances indentically configured?

One thing to check is if the instances have the same memory allocation.

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  • Yes they have the same memory configuration. I use the following query to check the mem configuration. SELECT * FROM sys.configurations where description like '%mem%' Commented Sep 29, 2011 at 11:48
  • Are all other configuration settings also identical?
    – Klas Lindbäck
    Commented Sep 29, 2011 at 11:55
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Odds are the statistics are out of date for one of the instances (or both) which is causing crappy execution plans to be generated.

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Use with(recompile) on the stored procedures to ensure they are both starting from scratch when it comes to the execution plans.

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