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Hi I have a Table with 2 columns, one column for the employeename and another column for shift, below is a sample.

EmployeeName          Shift
John                    1
Peter                   1
Mary                    2
Mike                    1
John                    2
Paul                    2
Mary                    1

I want to output it to query with 3 columns and count the number of shifts as show below:

EmployeeName         Shift1            Shift2
John                   1                 1
Peter                  1                 0
Mary                   1                 1
Mike                   1                 0
Paul                   0                 1 
  • (What do you want to happen if there are two rows with John, 1?) – Aaron Bertrand Jun 7 '14 at 15:10
  • John i have a table similar to these and need to count two conditions, so queries have different where clause need to combine them in 1 result. – Arvin Jun 7 '14 at 15:25
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In SQL Server 2012 you can use the new IIF() function:

SELECT EmployeeName, 
  Shift1 = COUNT(IIF(Shift=1,1,NULL)),
  Shift2 = COUNT(IIF(Shift=2,1,NULL))
FROM dbo.tablename
GROUP BY EmployeeName;

This is just shorthand for a CASE expression, so on older versions you could do it this way:

SELECT EmployeeName, 
  Shift1 = COUNT(CASE WHEN Shift = 1 THEN 1 END),
  Shift2 = COUNT(CASE WHEN Shift = 2 THEN 1 END)
FROM dbo.tablename
GROUP BY EmployeeName;

You can also use PIVOT:

SELECT EmployeeName, Shift1 = [1], Shift2 = [2] 
FROM dbo.TableName AS t
PIVOT (COUNT(Shift) FOR Shift IN ([1],[2])) AS p;

Now, none of these seems to produce the results in the same order you've defined in the question, and I don't know it's possible to produce that order reliably given the sample data you've shown.

# SQLfiddle demo #

  • Actually 1 and 2 works well, the pivot i can not get to work properly.. a million thanks, im trying to figure this one out for the past 2 days, btw i am new in sql – Arvin Jun 7 '14 at 15:49
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select EmployeeName, max(shift1) as shift1, max(shift2) as shift2
from (
    select EmployeeName
         , case when shift = 1 then 1 else 0 end as shift1
         , case when shift = 2 then 1 else 0 end as shift2
    from T
) as t2
group by EmployeeName

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