I have a table in database(oracle sql) which somehow contains one special character at the end which I dont know.I am trying to get that special character from its entry in table tab.

SQL> SELECT tname from tab where tname='OPERATION';

no rows selected

SQL> SELECT tname from tab where tname like 'OPERATION%';


SQL> SELECT length('OPERATION') from tab where tname like 'OPERATION%';


SQL> SELECT length(tname) from tab where tname like 'OPERATION%';


So , there is one special character after char N in string OPERATION . I tried getting the last character using substr but that did not help.

How can I find this special charater ( or even ascii value of this character ) ?

And how can I run select on the data in this table ?


1 Answer 1


You can try the dump function to get the actual byte values stored. For example, I just created a table "OOUPS ", with a space at the end.

> select table_name, dump(table_name) from user_tables;
OOUPS   Typ=1 Len=6: 79,79,85,80,83,32

You can see 32 (0x20 hex) as the last char - that's an ASCII space.

Once you've found what the extra character is, you can query the table using double quotes around the name. This is case-sensitive, so make sure you match that too. e.g.:

create table "OOUPS " (a int);
insert into "OOUPS " (a) values (42);
select * from "OOUPS ";

And of course:

alter table "OOUPS " rename to more_sane_name;

If you can't type the strange character easily, simplest way would be to create an SQL script, or pipe the exact character sequence to SQL*Plus:

OOUPS   Typ=1 Len=6: 79,79,85,80,83,13
$ echo -e 'alter table "OOUPS\r" rename to saner_name;\nexit;' | sqlplus user/pass
Table altered.

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