3

I'm running Oracle 11g. I have a table with two BLOB columns. I inserted 10,000 rows into the table, and each column contained a byte array of size 10289.

As you can see, there are 10,000 rows in the table and each column has 10,289 bytes in it:

SQL> select count(*) from MYUSER.MYTABLE;

  COUNT(*)
----------
     10000

SQL> select min(length(COL1)), min(length(COL2)) from MYUSER.MYTABLE;

MIN(LENGTH(COL1))      MIN(LENGTH(COL2))
-----------------      -----------------
            10289                  10289

Therefore the table should be using up at least 205MB of space (10289 bytes * 2 * 10000).

But I used the query given here to find out how much space the table is using, and I got the following:

SQL> SELECT SUM(bytes), SUM(bytes)/1024/1024 MB FROM dba_extents WHERE owner = 'MYUSER' AND segment_name = 'MYTABLE';

SUM(BYTES)         MB
---------- ----------
   2097152          2

Why does it say the table is using up just 2 MB when it should be using up 250 MB?

The byte arrays I'm inserting are compressed data, so Oracle couldn't possibly be compressing that data any further.

  • 1
    LOBs are stored out of row if they're bigger than 4k – Philᵀᴹ Mar 3 '15 at 22:36
5

Your table's segment is only 2 MB. The rest of the data is stored in the LOB segments which are physically separate from the table segment.

SELECT column_name, segment_name
  FROM dba_lobs
 WHERE owner = 'MYUSER'
   AND table_name = 'MYTABLE'

should show you that there are two LOB segments associated with the table. You can then query dba_segments to get the size of those segments

SELECT sum(bytes)/1024/1024 mb
  FROM dba_segments
 WHERE owner = 'MYUSER'
   AND segment_name IN (SELECT segment_name
                          FROM dba_lobs
                         WHERE owner = 'MYUSER'
                           AND table_name = 'MYTABLE')
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