Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with mongodb-3.6
Search options answers only
not deleted
user 138145
4
votes
Accepted
mongodb: update string field to integer
The solution is to use NumberInt instead of parseInt.
var coll = db.getCollection('info');
var bulk = coll.initializeOrderedBulkOp();
var counter = 0;
coll.find({ width_px: { $type: "string" }}).forE …
- 421
1
vote
Accepted
Howto specify my own id value when upload a stream into a gridfs file, using the GridFSBucke...
The solution is the openUploadStreamWithId method.It has this signature:
openUploadStreamWithId(id: GridFSBucketWriteStreamId, filename: string, options?: GridFSBucketOpenUploadStreamOptions): GridFS …
- 421