New answers tagged mysql-workbench
0
Basically
'column1' 'column2' 'column3' is different than 'column1,column2,column3'
So, you must compare the whole string:
BEGIN
IF (col_names = 'column1,column2,column3')
THEN
.
.
.
If you want to compare each variable separately, then you must pass them separate in your procedure call:
Call:
call hussian('prstate','table_1','column1','column2','...
1
This warning is shown for any other but the supported MySQL versions (at the time being these are 5.6, 5.7 and 8.0). The application uses language features and other resources that may or may not work with other servers. It's actually not tested, which is the main reason why this warning comes up.
MariaDB might be based on MySQL, but over time it more and ...
0
Try this
SELECT *
FROM list
WHERE DATEDIFF(ls_bday, CURRENT_DATE()) < 7
1
I hope you are looking for FIND_IN_SET().
SELECT *
FROM employees
WHERE FIND_IN_SET(dept_Id, @ZDept_Id);
0
Sounds like it is a syntax check complaining:
select * FROM project where name='Anna'
^^^^ -- missing syntax keyword!
0
IN ( SELECT ... ) is often an inefficient way to design a query. There are two alternatives below. Also, your IN was asking to fetch the entire array; this is probably causing terrible performance. You only need to check for the "existence" of one customer.
Note that each formulation checks for one "customer" in Table B and does not fetch the entire ...
Top 50 recent answers are included
