16

I've got the following JSON object:

{
    "a" : {
        "0" : 2,
        "1" : 4,
        "3" : 6,
    },
    "b" : {
        "2" : 8,
        "1" : 10, /*note this key exists in "a" too*/
        "4" : 12,
    }
}

I'd like to generate the following object and then be able to extract an element from it like so:

{
        "0" : 2,
        "1" : 10,
        "2" : 8,
        "3" : 6,
        "4" : 12,
}

Extraction: object->>'1' should return '10'

Basically, I have two arrays with potentially overlapping keys and I want to merge the two, giving one array precedence.

How can I accomplish this? Ideally I'd call a function like arrayMerge(a, b) and it gave 'a' higher precedence than 'b'

2

1 Answer 1

20

If you're using PostgreSQL 9.5 (at least), you can use the concatenation operator (||) on jsonb types (and you can convert json to jsonb if necessary first).

For example:

WITH test(data) AS (
    VALUES ('{
        "a" : {
            "0" : 2,
            "1" : 4,
            "3" : 6
        },
        "b" : {
            "2" : 8,
            "1" : 10,
            "4" : 12
        }
    }'::jsonb)
)
SELECT (data->'a') || (data->'b') FROM test

will produce:

{"0": 2, "1": 10, "2": 8, "3": 6, "4": 12}

(Please note that, in this particular example, the parentheses around (data->'a') matter.)

You can modify the example above to get a specific value, as you requested, for example:

SELECT (((data->'a') || (data->'b'))->'1')::text::integer FROM test
1
  • Thanks for your comment about the the parentheses around (data->'a') which really matter! It saved me a few minutes more of head scratching Commented Feb 3, 2021 at 21:15

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.