Schema
I have the following set-up in MySQL database:
CREATE TABLE items (
id SERIAL,
name VARCHAR(100),
group_id INT,
price DECIMAL(10,2),
KEY items_group_id_idx (group_id),
PRIMARY KEY (id)
);
INSERT INTO items VALUES
(1, 'Item A', NULL, 10),
(2, 'Item B', NULL, 20),
(3, 'Item C', NULL, 30),
(4, 'Item D', 1, 40),
(5, 'Item E', 2, 50),
(6, 'Item F', 2, 60),
(7, 'Item G', 2, 70);
Problem
I need to select:
- All items with
group_id
that hasNULL
value, and - One item from each group identified by
group_id
having the lowest price.
Expected results
+----+--------+----------+-------+
| id | name | group_id | price |
+----+--------+----------+-------+
| 1 | Item A | NULL | 10.00 |
| 2 | Item B | NULL | 20.00 |
| 3 | Item C | NULL | 30.00 |
| 4 | Item D | 1 | 40.00 |
| 5 | Item E | 2 | 50.00 |
+----+--------+----------+-------+
Possible solution 1
Two queries with UNION ALL
:
SELECT id, name, group_id, price FROM items
WHERE group_id IS NULL
UNION ALL
SELECT id, name, MIN(price) FROM items
WHERE group_id IS NOT NULL
GROUP BY group_id;
/* EXPLAIN */
+----+--------------+------------+------+--------------------+--------------------+---------+-------+------+----------------------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+--------------+------------+------+--------------------+--------------------+---------+-------+------+----------------------------------------------+
| 1 | PRIMARY | items | ref | items_group_id_idx | items_group_id_idx | 5 | const | 3 | Using where |
| 2 | UNION | items | ALL | items_group_id_idx | NULL | NULL | NULL | 7 | Using where; Using temporary; Using filesort |
| NULL | UNION RESULT | <union1,2> | ALL | NULL | NULL | NULL | NULL | NULL | |
+----+--------------+------------+------+--------------------+--------------------+---------+-------+------+----------------------------------------------+
However it is undesirable to have two queries since there will be more complex condition in WHERE
clause and I would need to sort the final results.
Possible solution 2
GROUP BY
on expression (reference)
SELECT id, name, group_id, MIN(price) FROM items
GROUP BY CASE WHEN group_id IS NOT NULL THEN group_id ELSE RAND() END;
/* EXPLAIN */
+----+-------------+-------+------+---------------+------+---------+------+------+---------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+-------+------+---------------+------+---------+------+------+---------------------------------+
| 1 | SIMPLE | items | ALL | NULL | NULL | NULL | NULL | 7 | Using temporary; Using filesort |
+----+-------------+-------+------+---------------+------+---------+------+------+---------------------------------+
Solution 2 seems to be faster and simple to use but I'm wondering whether there is a better approach in terms of performance.
Update: According to MySQL documentation, this query is illegal in SQL92 and earlier and may work in MySQL only.
group_id
and same lowestprice
)?group_id
was thePRIMARY KEY
or aUNIQUE NOT NULL
column. But then you wouldn't need thegroup by
;)